Trade height for speed

Conservation of energy, explained.

Gravity transfers energy from potential to kinetic form as height decreases. On a frictionless ramp, total mechanical energy stays constant. A steeper ramp changes acceleration and travel time, but the speed at the bottom depends only on the vertical drop.

Schematic ramp · h = 4.69 mENERGY / JPotential91.97 JKinetic6.13 JTotal: 98.1 J

The relationship to remember

mgh₀ = mgh + ½mv²

Key formulas

Gravitational potential energy
PE = mgh
h measured from a chosen reference level
Kinetic energy
KE = ½mv²
Never negative
Conservation of mechanical energy
PE₀ + KE₀ = PE + KE
No friction or drag
Speed after a drop from rest
v = √(2gΔh)
Mass cancels
Acceleration along the ramp
a = g sin θ
Sets the travel time, not the final speed

Worked example

Problem. A 2 kg block starts from rest 5 m above the bottom of a frictionless ramp. Find its kinetic energy and speed halfway down (2.5 m high) and at the bottom.

  1. Total mechanical energy: mgh₀ = 2 × 9.81 × 5 = 98.1 J.
  2. Halfway down: PE = 2 × 9.81 × 2.5 = 49.05 J, so KE = 98.1 − 49.05 = 49.05 J.
  3. Speed halfway: v = √(2KE/m) = √(2 × 49.05 / 2) = 7.00 m/s.
  4. At the bottom all 98.1 J is kinetic: v = √(2 × 9.81 × 5) = 9.90 m/s.

Answer. Halfway down the block has 49.05 J of kinetic energy and moves at 7.00 m/s; at the bottom it reaches 9.90 m/s.

A quick check

Dropping through 5 m gives a final speed of √(2 × 9.81 × 5) ≈ 9.90 m/s, regardless of mass in this model.

Inside the default experiment

  1. Total energy = mgh₀ = 2 × 9.81 × 5 = 98.1 J.
  2. At height 4.69 m, potential energy = 91.97 J. Kinetic energy = 98.1 − 91.97 = 6.13 J.
  3. Speed = √(2g(h₀ − h)) = 2.48 m/s. Travel time to the bottom = 2.02 s.

When this model applies

A sliding point mass starts from rest. No friction, air drag, or rotational energy; g = 9.81 m/s².

Make a prediction. Then test it.

Change the ramp angle but keep its height. Does the final speed change?

Try it: Conservation of energy on a ramp ↗
A little question. A clearer picture.

Frequently asked questions

Wondering about the why? Start here.

Why does mass not affect the final speed?

Equating mgh to ½mv² lets mass cancel. Both available potential energy and required kinetic energy grow in proportion to mass.

Where does the energy go if there is friction?

Some mechanical energy is transferred into thermal energy and other forms. This experiment deliberately excludes those losses.