Trade height for speed

Conservation of energy on a ramp

Slide a block down a frictionless ramp and watch gravitational potential energy turn into kinetic energy while the total stays constant. Conservation of mechanical energy gives mgh₀ = mgh + ½mv², so the speed after a vertical drop Δh is v = √(2gΔh), whatever the mass or the ramp angle.

Printable classroom activity ↗
Energy on a rampTRY IT YOURSELF
Schematic ramp · h = 4.69 mENERGY / JPotential91.97 JKinetic6.13 JTotal: 98.1 J
0.50 s
Height4.688 m
Speed2.476 m/s
Kinetic energy6.131 J
Potential energy91.969 J
Teal + amber · follow the changing valuesIdealized physics model

What if you changed…

Try a starting point

YOUR NEXT AHA

Change the ramp angle but keep its height. Does the final speed change?

See the calculation

mgh₀ = mgh + ½mv²
  1. Total energy = mgh₀ = 2 × 9.81 × 5 = 98.1 J.
  2. At height 4.69 m, potential energy = 91.97 J. Kinetic energy = 98.1 − 91.97 = 6.13 J.
  3. Speed = √(2g(h₀ − h)) = 2.48 m/s. Travel time to the bottom = 2.02 s.

What this model assumes

A sliding point mass starts from rest. No friction, air drag, or rotational energy; g = 9.81 m/s².

Keep an eye on this

A real rolling ball also stores rotational kinetic energy, so this sliding-particle model does not predict its exact speed.

Understand the physics ↗
Forces & energy

Formulas used in this simulation

Gravitational potential energy
PE = mgh
h measured from a chosen reference level
Kinetic energy
KE = ½mv²
Never negative
Conservation of mechanical energy
PE₀ + KE₀ = PE + KE
No friction or drag
Speed after a drop from rest
v = √(2gΔh)
Mass cancels
Acceleration along the ramp
a = g sin θ
Sets the travel time, not the final speed
Formulas explained with a worked example ↗
A little question. A clearer picture.

Energy on a ramp: common questions

Wondering about the why? Start here.

How do you find speed from height?

Set the potential energy lost equal to the kinetic energy gained: mgΔh = ½mv². Mass cancels, leaving v = √(2gΔh). A 5 m drop gives about 9.9 m/s.

Does a steeper ramp make the block faster at the bottom?

Not on a frictionless ramp. A steeper ramp gives a larger acceleration, g sin θ, and a shorter trip, but the final speed depends only on the vertical drop.

Is mechanical energy always conserved?

Only when forces such as friction and air resistance do no work. Otherwise some energy is transferred to thermal energy and the final speed is lower.

Why does mass not affect the final speed?

Equating mgh to ½mv² lets mass cancel. Both available potential energy and required kinetic energy grow in proportion to mass.

Where does the energy go if there is friction?

Some mechanical energy is transferred into thermal energy and other forms. This experiment deliberately excludes those losses.