Read the motion

Position, velocity & acceleration, explained.

Velocity is the rate of change of position, and acceleration is the rate of change of velocity. A negative acceleration can slow an object traveling in the positive direction, then make it speed up in the negative direction.

POSITION / mVELOCITY / m/s0 s6 s+30−300 s6 s+8−8

The relationship to remember

x = v₀t + ½at² · v = v₀ + at

Key formulas

Velocity at time t
v = v₀ + at
The v–t graph has slope a
Position at time t
x = x₀ + v₀t + ½at²
This lab starts at x₀ = 0
Velocity without time
v² = v₀² + 2a(x − x₀)
Use when the time is unknown
Average velocity
v̄ = Δx/Δt = (v₀ + v)/2
Second form needs constant a
Displacement from a v–t graph
Δx = area under the v–t graph
Area below the axis counts as negative
Turnaround time
t = −v₀/a
When v₀ and a have opposite signs

Worked example

Problem. A cart moving at +6 m/s has a constant acceleration of −2 m/s². When does it turn around, how far out does it get, and where is it after 6 s?

  1. It turns around when v = 0: 0 = 6 + (−2)t, so t = 3 s.
  2. Position at the turnaround: x = 6 × 3 + ½ × (−2) × 3² = 18 − 9 = 9 m.
  3. After 6 s: x = 6 × 6 + ½ × (−2) × 6² = 36 − 36 = 0 m, and v = 6 + (−2) × 6 = −6 m/s.
  4. Displacement over the 6 s is 0 m, but the distance travelled is 9 m out plus 9 m back = 18 m.

Answer. The cart turns around at t = 3 s, 9 m from the start, and is back at x = 0 moving at −6 m/s after 6 s.

A quick check

With initial velocity 2 m/s and acceleration 1 m/s², after 4 s the position is 16 m and the velocity is 6 m/s.

Inside the default experiment

  1. At t = 1.5 s: x = 2 × t + ½ × 1 × t² = 4.13 m.
  2. v = 2 + 1 × 1.5 = 3.5 m/s.
  3. End displacement at 6 s = 30 m.

When this model applies

One-dimensional motion starting at x = 0 with constant acceleration.

Make a prediction. Then test it.

Give the object positive velocity and negative acceleration. When does it turn around?

Try it: Position, velocity & acceleration graphs ↗
A little question. A clearer picture.

Frequently asked questions

Wondering about the why? Start here.

What does the slope of a position graph mean?

The slope is velocity. A steeper upward slope means a larger positive velocity; a downward slope means negative velocity.

Is displacement the same as distance?

Displacement is final position minus initial position. Distance is the total length traveled, so reversing direction makes the two different.